(2x-2)^2+4=18

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Solution for (2x-2)^2+4=18 equation: 



(2x-2)^2+4=18

We move all terms to the left:

(2x-2)^2+4-(18)=0

We add all the numbers together, and all the variables

(2x-2)^2-14=0

We move all terms containing x to the left, all other terms to the right

(2x-2)^2=14

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